Aspeed boat travels with a speed of 6 m/s travels directly north to cross a river flowing west with a current traveling at a speed of 3 m/s. what is the resultant velocity of the boat?

6.7 m/s @ 116.6°

Explanation:

Use Pythagorean theorem to find the magnitude:

v² = vx² + vy²

v² = (-3 m/s)² + (6 m/s)²

v = √45 m/s

v ≈ 6.7 m/s

Use trigonometry to find the direction:

θ = atan(vy / vx)

θ = atan(6 m/s / -3 m/s)

θ = atan(-2)

θ ≈ 116.6° from the +x axis, or 63.4° north of west.

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s