Aball with an initial velocity of 25 m/s is subject to an acceleration of -9.8m/s^2 how high does it go before coming to a momentary stop ?

The ball will reach an height of 31.88 meters before coming to a stop.

Explanation:

we know that by equation of motion

where v is the final velocity of the ball , u is the initial velocity of the ball , a is acceleration due to gravity and s is the distance traveled by the ball.

a = -9.8

and u = 25 m/s

and v = 0

therefore s =

so s = 31.88 meters

learn it on the intertant so you can solve

that would be because of both gravity and friction. so     c