Ablock starts at rest and slides down a frictionless track. it leaves the track horizontally, flies through the air, and subsequently strikes the ground. b b b b b b b b b b b b 472 g 4.1 m 1.8 m x v what is the speed of the block when it leaves the track? the acceleration of gravity is 9.81 m/s 2 . answer in units of m/s

Explanation:

Time required by the ball to reach the bottom of the track is given as

now the speed of the ball is given as

here we have

d = 1.8 m

so we have

explanation:

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  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂