The drawing shows three identical springs hanging from the ceiling. nothing is attached to the first spring, whereas a 4.00-n block hangs from the second spring. a block of unknown weight hangs from the third spring. from the drawing, determine (a) the spring constant (in n/m) and (b) the weight of the block hanging from the third spring.

K = 26.667 N/m

Explanation:

a) Using the newton's laws:

Where W is the weigth of the block in the second spring and is the force of that spring. So:

W =

It means that:

W =

where K is the constant of the spring and x2 is the deformation of the second spring. Then, replacing values we get:

4N = K(0.15m)

Solving for K:

K = 26.667 N/m

b) At the same way, for the third spring, we have the equation:

W =

Where K is the same constant of the secor spring and x3 is the deformation of the third spring.

Finally, replacing values, we get:

W = (26.667N/m)(0.30)

W = 8N

the body's situation won't change the forces are equal opposit and on the same body

i will answer your question if you answer mine