Physics, 13.12.2019 21:31 SapphireWolf

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Answer from: aliopqwas

1) The mass of the skier, m = 51.02 kg

2) At top of the hill, v = 0

3) The velocity of the skier at the 30 m height, v = 37.04 m/s

4) The velocity of the skier at the bottom of the hill, v = 44.27 m/s

Explanation:

Given data,

The initial height of the skier from the ground, h = 100 m

The K.E of skier at 100 m = 0 J

The P.E of the skier at 100 m = 50,000 J

1) The mass of the skier,

m = P.E/ gh

= 50,000/ (9,8 x 100)

= 51.02 kg

2) The velocity of the skier at the top of the hill,

At top of the hill, the K.E = 0,

Hence,

v = 0

3) The velocity of the skier at the 30 m height,

P.E = mgh

= 51.02 x 9.8 x 30

= 14,999.88 J

E = P.E + K.E

K.E = E - P.E

= 50,000 - 14,999.88

= 35000.12 J

v = √(2 K.E/m)

= √(2 x 35000.12 / 51.02)

v = 37.04 m/s

4) The velocity of the skier at the bottom of the hill,

At bottom of the hill, P.E = 0 and K.E is maximum

K.E = 50,000 J

v = √(2 K.E/m)

= √(2 x 50000 / 51.02)

v = 44.27 m/s

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scientific laws are the result of testing theories and proving them to be facts.

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