Aproton and an electron are located 12 nm apart. calculate the force of attraction between them?

The force between them is, F = 8.33 x 10⁻¹¹ N

Explanation:

Given data,

The distance between the proton and electron, x = 12 nm

                                                                                   = 12 x 10⁻⁹ m

The electrostatic force between them is given by the formula,

Where k = 9 x 10⁹ Nm²C⁻²

Substituting the given values,

                                    F = 8.33 x 10⁻¹¹ N  

Hence, the force between them is, F = 8.33 x 10⁻¹¹ N                                          

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