A)a certain medical machine emits x-rays with a minimum wavelength of 0.024 nm. one day, the machine has an electrical problem and the voltage applied to the x-ray tube decreases to 76% of its normal value. now what is the minimum x-ray wavelength produced by the machine?

lmin =

(b) what is the maximum x-ray energy this machine (with electrical problems) can produce?

emax = ev

(c) the atomic number of an element is 82. according to the bohr model, what is the energy of a ka x-ray photon?

e = ev

(a) 0.032 nm

(b) 39,235 eV

(c) 70,267.8 eV

Explanation:

(a) The energy of a photon can be calculated using:

E = hc/λ                  equation (1)

where:

h = 4.13*10^-15 eV.s

c = 3*10^8 m/s

λ = 0.024*10^-9 m

Thus:

E = (4.13*10^-15)*(3*10^8)/0.024*10^-9 = 51,625 eV

Then we calculate 76% of this estimated energy and determine the new wavelength:

Using equation (1) to determine the new wavelength:

λ

λ = (4.13*10^-15)*(3*10^8)/39235 = 3.15*10^-11 m = 0.032 nm

(b) As calculated in part (a), the maximum x-ray energy this machine can produce is

(c)  The energy of a Ka x-ray photon can be estimated using:

where Z is the atomic number = 84.

= 70,267.8 eV

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.