Ineed answers for the problems listed below

(27)

(28)

(29)

(30)

Explanation:

Projectile Motion: When a body is launched in air at an angle with the horizontal  with speed ,It makes a certain trajectory in influence of gravity.

Time of flight of projectile,

Maximum height of projectile,

Horizontal range of projectile,

Given,

Distance of final position of salmon from base of cliff,

Height of cliff,

If the salmon is launched horizontally, the vertical component of velocity will be zero.

Using second equation of motion,

Let horizontal component of velocity is . Time taken to reach 90 meter away from base is 5 second.

So,

Hence, Velocity,

Given,

Initial velocity,

Angle,

(a)

Totle time,

So, Rocket's totle time in the air is 4.48 second.

(b)

Maximum height,

So, Rocket's maximum height is 33.58 meter.

(c)

Range,

So, Rocket will land 91.6 meter away.

Given,

Since, It started from rest, then initial velocity

Acceleration,

Distance traveled,

Using third equation of motion

So, Final velocity is 23.96m/s.

Given,

Range of trebuchet,

Time of flight,

Now,

Put value

Hence

(a) Peak height is 24.8 meter.

(b) Initial angle is 23.45°.

(c) Initial velocity is 55.4m/s

1.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2