Suppose you and a friend, each of mass 60 kg, go to the park and get on a 4.0-m-diameter merry-go-round. you stand on the outside edge of the merry-go-round, while your friend pushes so that it rotates once every 6.0 s. what is the magnitude of the (apparent) outward force that you feel?
a. 7 n
b. 63 n
c. 130 n
d. 260 n

The magnitude of centripetal force is 130 N.

Explanation:

It is given that,

Mass, m = 60 kg

Diameter of the merry go round, d = 4 m

Radius, r = 2 m

Time for rotation, t = 6 s

We know that we will feel some of the outward force and this force is known as centripetal force. Its formula is given by :

v is the velocity

v = 2.09 m/s

F = 131.04 N

or

F = 130 N

So, the magnitude of centripetal force is 130 N. Hence, this is the required solution.

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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