)a skier starts down a frictionless 32° slope. after a vertical drop of 25 m, the slope temporarily levels out and then slopes down at 20°, dropping an additional 38 m vertically before leveling out again. find the skier’s speed on the two level stretches

The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.

Explanation:

Given that,

Slope down = 32°

Height = 25 m

Before leveling,

Slope down = 20°

Height = 38 m

We need to calculate the skier’s speed on the two level stretches

Using formula of energy

For first stretch,

Height = 25 m

Put the value into the formula

For second stretch,

Height = 38 m

Put the value into the formula

Hence, The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s