Aspinning top rotates so that its edge turns at a constant speed of 0.63 m/s. if the top has a radius of 0.10 m, what is the
centripetal acceleration of the edge of the top?
o 0.016 m/s2
0.73 m/s2
4.0 m/s2
6.3 m/s2

The  centripetal acceleration of the edge of the top

Explanation:

Given:

Speed with which the top rotates =  0.63 m/s

Radius of the top = 0.10 m

To Find:

Centripetal acceleration of the edge of the top =?

Solution:

The centripetal acceleration is the rate at which the tangential velocity changes. Also its direction is always inwards along the radius vector of the circular motion.

We know that centripetal acceleration is

Where

v = velocity

r = radius

Substituting the values

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s