An object is thrown directly upwards from the ground at a velocity of 9ms. Recalling that the acceleration due to gravity is −gms2, find the time at which the object reaches its maximum height. What is this maximum height? Your answers should be in terms of g.

Explanation:

Given

Object is thrown with a velocity of

Acceleration due to gravity is -g (i.e. acting downward)

Vertical distance traveled by object is given by

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

at maximum height final velocity is zero

time taken to reach maximum height

using

v=u+at

0=9-gt

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete