(a) A 10.0-mm-diameter Brinell hardness indenter produced an indentation 2.4 mm in diameter in a steel alloy when a load of 1000 kg was used. Compute the HB of this material. (b) What will be the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used?

(a). The HB of this material is 217.8

(b). The diameter of an indentation is 1.45 mm.

Explanation:

Given that,

Diameter of Brinell hardness D= 10.0 m

Diameter of steel alloy d= 2.4 mm

Load = 1000 kg

(a). We need to calculate the HB of this material

Using formula of Brinell hardness

Put the value into the formula

(b). Given that,

Hardness = 300 HB

Load = 500 kg

We need to calculate the diameter of an indentation

Using formula of diameter

Put the value into the formula

Hence,(a). The HB of this material is 217.8

(b). The diameter of an indentation is 1.45 mm.

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

it's a b and