A 1.0-m-long copper wire of diameter 0.10 cm carries a current of 50.0 A to the east. Suppose we apply to this wire a magnetic field that produces on it an upward force exactly equal in magnitude to the wire's weight, causing the wire to "levitate."Is the direction to the North, South, East or West?

The direction of the magnetic field that would cause the wire carrying current due east to levitate upwards is in the **Northern direction**

Explanation:

The principle/rule that explains this is called the right hand rule. And it is used for three dimensions that are known to be perpendicular to each other like the x,y,z coordinates in coordinate system and for magnetic field, firstly, the force on a charge, F, its velocity in a magnetic field, v, and the direction of the magnetic field, B, can all have their directions predicted correctly using the right hand rule and secondly, just like for this question, the force on a current carrying wire, F, the direction in which its current are flowing, and the direction of the magnetic field.

The right hand rule uses the first three fingers on the right hand (the thumb, the pointing finger and the middle finger) and it predicts correctly that for current carrying wires, the thumb is in the direction the wire is pushed (direction of the force; which levitating upwards for this question), the pointing finger is in the direction the current is flowing (east for this question), and the middle finger is in the direction of the magnetic field (hence, the northern direction).

answer; i believe the correct answer is (40,000 j) good luck