Physics, 27.02.2020 17:21 Sk8terkaylee

A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.

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Answer from: nancyy85

What is the first event that will occur? Assume non zero Nonzero frictional force and the same coefficient of friction for both bugs

a. The lady bug begins to slide

b. The gentleman bug begins to slide

c. Both bugs begin to slide at the same time

d. Nothing ever happens

e. Not enough information to determine

The correct answer to the question is

a. The lady bug begins to slide

Explanation:

To solve the question we have to write out the forces acting on the bugs

The frictional force is given by

f = μN = m×g×μ and the centripetal force is given by $F_c=\frac{mv^2}{r}$

For equilibrium the two forces are equal and the bugs remain, that is

m×g×μ = $\frac{mv^2}{r}$ canceling like terms gives g×μ = $\frac{v^2}{r}$ = ω²r

Therefore as the acceleration increases the centripetal force will eventually exceed the frictional force

therefore for the ladybug, if the distance from the center = r then

g×μ = ω²r

while for the gentleman bug we have the radius = r/2, therefore

g×μ = ω²r/2 or the centripetal force is half of that of the ladybug hence the effect of the frictional force is grater on the gentleman bug than on the ladybug for the same angular velocity

which means the ladybug begins to slide first as it has two times the centripetal force of the gentleman bug to overcome the force of friction

Answer from: Quest

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

Answer from: Quest

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass $= 2\%\hspace{1mm}of \hspace{1mm} 70\hspace{1mm} kg=\frac {2}{100}\times 70 =1.4\hspace{1mm} kg$

therefore, 100 trillion micro-organisms would weigh:

$\rightarrow 100\times1.4 kg = 140 kg$

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism = $\frac{1.4 kg}{10^12}=1.4\times10^{-12} kg$

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