A plastic rod that has been charged to−15.0nCtouches a metal sphere. Afterward, the rod’s charge is−10nC. Chargeonelectronis1.6x10-6C. What kind of charged particle was transferred between the rod and the sphere, and in which direction? That is, did it move from the rod to the sphere or from the sphere to the rod?How manycharged particles were transferred?

Answer 1 : electrons was transfered from the rod to the metal inducing a positive charge on the metal surface close to the rod.

Explanation: in static electricity, electron always flows to or away from a particle. In this case, the charge rod contains loose excited electrons. On contact with the metal surface, most of the free electrons move from the rod to the metal to even up the charge on the rod. This leaves a positive induced charge on the metal surface in contact with the rod.

Answer 2: approximately 3*10^10 electrons were transfered.

Explanation: the initial charge on the rod was -15nC = -15*10^-9C

Final charge = -10nC = -10*10^-9C

Charges lost = -10nC - (-15nC) = 5nC of charges.

Charge on an electron particle = -1.6*10^-19 the minus indicates that the electron carries a negative charge.

Total number of particles transfered becomes;

n = (5*10^-9)/(1.6*10^-19) = 3.125 *10^10 electron

Approximately 3*10^10 electrons.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.