1. Vertically oriented circular disks have strings wrapped around them. The other ends of the strings are attached to
hanging masses. The diameters of the disks, the masses of the disks, and the masses of the hanging masses are
given. The disks are fixed and are not free to rotate. Specific values of the variables are given in the figures.

See the answers and explanation below

Explanation:

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Description of the problem

"Vertically oriented circular disks have strings wrapped around them. The other ends of the strings are attached to  hanging masses. The diameters of the disks, the masses of the disks, and the masses of the hanging masses are

given. The disks are fixed and are not free to rotate. Specific values of the variables are given in the figures. Rank these situations, from greatest to least, on the basis of the magnitude of the torque on the disks. That is, put first the situation where the disk has the greatest torque acting on it and put last the situation where the disk has the least torque acting on it."

For case D

T = (20/2)*800 = 8000 [g-cm]

For case A

T = (20/2)*500 = 5000 [g-cm]

For case C

T = (10/2)*500 = 2500 [g-cm]

For case B

T = (10/2)*200 = 1000 [g-cm]

In this way it has been organized from the largest to the smallest torque present in each of the cases.

it breaks and dirupture other materials and other sencews from the bottom