The 10-lb block has a speed of 4 ft>s when the force of F = (8t2) lb is applied. Determine the velocity of the block when it moves s = 30 ft. The coefficient of kinetic friction at the surface is ms = 0.2.

The velocity of the block is 231650.8 ft/s

Explanation:

Knowing

W = 10 lb

v0 = u = 4 ft/s

F = 8 lb

ms = 0.2

Applying the newton second law

ΣFy = 0

N - W = 0 --> N = W = 10 lb

ΣFx = m

F - ms N = ma

- 0.2(10) =

a =

Using Kinematics

a = dv/dt

= =

v - 4 = 3.22

when t = 30

v = 231650.8 ft/s

c

explanation: