A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distance d away. The bear is 29 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d

Explanation:

It is known that the relation between speed and distance is as follows.

               velocity =

As it is given that velocity is 6 m/s and distance traveled by the bear is (d + 29). Therefore, time taken by the bear is calculated as follows.

          ............. (1)

As the tourist is running in a car at a velocity of 4.2 m/s. Hence, time taken by the tourist is as follows.

              ............. (2)

Now, equation both equations (1) and (2) equal to each other we will calculate the value of d as follows.

        =

                   4.2d + 121.8 = 6d

                         d =

                            = 67.66

Thus, we can conclude that the maximum possible value for d is 67.66.

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