A 80 gg bungee cord has an equilibrium length of 1.20 mm. The cord is stretched to a length of 1.80 mm, then vibrated at 17 HzHz . This produces a standing wave with two antinodes. Part A What is the spring constant of the bungee cord?

the part of the wave he is travelling on is the crest

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s