G A steel rod of 0.5 cm diameter and 10 m length is stretched 3 cm. Young’s modulus for this steel is 21 kN/cm2. How much work, in kJ, is required to stretch this rod?

Explanation:

Formula for work using change in volume and Young's modulus is as follows.

        W =

             =

             =

             = 0.124 kJ

Therefore, we can conclude that 0.124 kJ work is required to stretch this rod.

The work done is

Explanation:

Given that,

Length = 10 m

Diameter = 0.5 cm

Young modulus = 21 kN/cm²

Stretched length = 3 cm

We need to calculate the wok done

Using formula of work done

...(I)

We know the deformation is,

Where,

Put the value in the equation (I)

Where,

E = Young modulus

d = diameter

l = length

Put the value into the formula

Hence, The work done is

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