Two capacitors with capacitances of 1.5 mF and 0.25 mF, respectively, are connected in parallel. The system is connected to a 50-V battery. What electrical potential energy is stored in the 1.5-mF capacitor?

Energy U = 1.875J

Explanation:

The voltage applied across the capacitors is the same and equal to 50V. The energy stored in a capacitor is given by

U = 1/2×CV²

So on substituting the required quantities into the equation we get U.

See attachment below.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.