An armada of spaceships that is 1.60 ly long (in its rest frame) moves with speed 0.800c relative to the ground station in frame S. A messenger travels from the rear of the armada to the front with a speed of 0.910c relative to S. How long does the trip take as measured (a) in the messenger's rest frame, (b) in the armada's rest frame, and (c) by an observer in frame S?

(a). The trip take a time is 3.61 year.

(b). The trip take a time is 3.96 year.

(c). The trip take a time is 8.73 year.

Explanation:

Given that,

Length = 1.60 ly

Speed of spaceships= 0.800c

Speed of messenger = 0.910 c

(a). We need to calculate the velocity of armada

Using formula of velocity

Put the value into the formula

We need to calculate the length

Using formula of length

Put the value into the formula

We need to calculate the length of the trip

Using formula of time

Put the value into the formula

(b). If the armada's rest frame

We need to calculate the length

Using formula of length

Put the value into the formula

Using formula of time

Put the value into the formula

(c). If an observer in frame S

We need to calculate the length

Using formula of length

Put the value into the formula

We need to calculate the time

Hence, (a). The trip take a time is 3.61 year.

(b). The trip take a time is 3.96 year.

(c). The trip take a time is 8.73 year.

no

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