A cube has a drag coefficient of 0.8. What would be the terminal velocity (in m/s) of a jumbo sugar cube 5-cm per side in air. The density of air is 1.2 kg/m3 and the density of sugar is 1600 kg/m3. Round your answer to the nearest tenth.

Explanation:

Formula for Terminal Velocity is given as :

Mass of sugar =  Density x Volume

Volume of cube = 5cm x 5cm x 5cm = 125  = 0.000125

Mass of sugar cube = 1600 kg/ x 0.000125 = 0.2 kg

Area = 5cm x 5 cm = 25 = 0.0025

V = 2 x 0.2 x 9.81 )/ (1600 x 0.0025 x 0.8)

V = 3.924/32) =

V= 0.350 m/s

The terminal velocity of the sugar would be 40.4 m/s

Explanation:

Given L as the length of the cube = 0.05 m

Area of the sugar = = 0.0025

The volume of the cube = = = 0.000125

Mass of the sugar = Density x volume  =1600 kg/ x 0.000125

The terminal velocity of a body can be calculated with the expression below;

Where;

m is the mass of the body = 0.2 kg

g is the acceleration due to gravity = 9.81 m/

p is the density of the fluid (air) = 1.2 kg/

A is the area of the body = 0.0025

Given L as the length of the cube = 0.05 m

Volume of the cube = = = 0.000125

Substituting the values in the equation, we have;

V = 40.4 m/s to the nearest tenth

Therefore the terminal velocity of the sugar would be

40.4 m/s

the answer is a)

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