Two toy cars (m1 = 0.200 kg and m2 = 0.250 kg) are held together rear to rear with a compressed spring between them. When they are released, the cars are free to roll away from the ends of the spring.
If you measure the acceleration of the 0.200-kg car to be 2.65 m/s2 to the right, what is the acceleration of the other car?

Acceleration of the second particle at that moment is given as

Explanation:

As we know that both cars are connected by same spring

So on this system of two cars there is no external force

So we will have

now we have

now we have

so we have

to treat tumors in the body

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form