A playground merry-go-round of radius R = 1.40 m has a moment of inertia I = 265 kg · m2 and is rotating at 11.0 rev/min about a frictionless vertical axle. Facing the axle, a 27.0-kg child hops onto the merry-go-round and manages to sit down on the edge. What is the new angular speed of the merry-go-round?

The value of new value of angular speed of merry go round. = 0.96

Explanation:

Given data

r = 1.4 m

Moment of inertia = 265 kg -

11 RPM

= 1.15

From conservation of momentum principal

------- (1)

Put all the values in equation  (1)

265 × 1.15 = 317.92 ×

= 0.96

This is the value of new value of angular speed of merry go round.

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