You're having a hard time pushing a refrigerator across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N. If the refrigerator has a mass of 355 kg, what is the refrigerator's acceleration

The acceleration of the refrigerator is

Explanation:

The expression of the equation of the net force acting on the refrigerator is as follows;

F-f= ma

Here, F is the applied force, f is the force of friction, m is the mass and a is the acceleration.

It is given in the problem that you're having a hard time pushing a refrigerator having mass 355 kg across the kitchen floor. The force of your own push is 993 N. The force of friction opposing your own push is 973 N.

Put F= 993, f= 973 N and m = 355 kg in the above expression of the equation to calculate the acceleration of the refrigerator.

993 - 973 = (355)a

20 = 355 a

Therefore, the acceleration of the refrigerator is .

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j