The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.8° what is the index of refraction of the material?

the index of refraction of the material is 1.53

Explanation:

c=40.8 degree

c = sin⁻¹ (n2/n1)

n2=1

then

For total internal reflection

sin40.8 = 1 / n1

0.6534 = 1 / n1

n1 = 1 / 0.6534

n1 = 1.53

Thus, the index of refraction of the material is 1.53

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach