What will be the amount of heat required to raise the temperature of 3 kg of paraffin by 10 degree C if 44000joules of heat energy is required to raise the temperature of 1 kg of paraffin by 20 degree C

66000 J

Explanation:

Firstly we look for the specific heat capacity of paraffin,

Q = cm(ΔФ) Equation 1

Where Q = energy required to raise the temperature of paraffin, c = specific heat capacity of paraffin, m = mass of paraffin, ΔФ = change in temperature.

make c the subject of the equation,

c = Q/(mΔФ) Equation 2

Given: Q = 44000 Joules, m = 1 kg, ΔФ = 20 °C

Substitute into equation 2

c = 44000/(1×20)

c = 2200 J/kg.°C

When,

m = 3 kg, ΔФ = 10 °C

substitute into equation 1

Q = 2200(3)(10)

Q = 66000 J.

Hence the amount of heat  required = 66000 J

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be