The emf of a particular flashlight battery is 1.5 volts. If the battery is 5.0 cm long, and the radius of the cylindrical battery is 1 cm, estimate roughly the amount of charge on the positive end plate of the battery.

The amount of charge is  

Explanation:

 Here let estimate that the battery is a parallel whose plates are of area = substituting value  

And the this plates are separated by a length d= 5.0cm

Now looking at this estimate we can see that the setup looks like a capacitor

    So to calculate the capacitance of our estimated capacitor we have

Where is the permitivity of free space with value

substituting values

The charge is mathematically represented as

Substituting values

i'm thinking more like energy

v=ir = 3x15 =45 v