A 0.140 kg baseball is thrown with a velocity of 33.6 m/s. It is struck with an average force of 5000.0 N, which results in a velocity of 37.0 m/s in the opposite direction. How long were the bat and ball in contact?

0.00198 secs

Explanation:

Parameters given:

Mass of baseball, m = 0.14 kg

Initial velocity of baseball, u = 33.6 m/s

Force applied to baseball, F = -5000 N

(The force is applied in an opposite direction to the initial velocity)

Final velocity, v = -37 m/s

Using the impulse-momentum theory, we have that the impulse applied to the baseball is equal to the change in momentum of the baseball:

FΔt = m(v - u)

Time interval, Δt, will be given as:

Δt =

Δt =

Δt =

Δt =

Δt =

The bat and the baseball were in contact for 0.00198 secs.

trig 15.3 cos

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it