Find the magnitude of the magnetic flux through the floor of a house that measures 25 m by 15 m . Assume that the Earth's magnetic field at the location of the house has a horizontal component of 3.0×10−5 T pointing north, and a downward vertical component of 3.9×10−5 T .

0.0185 Wb

Explanation:

The magnitude of the magnetic flux through the floor of the house is given as:

|Φ| = |B| * A

Where B is the magnetic field through the floor and A is the area of the floor.

Magnetic field, B, is a vector and it is given as:

B = (3.0 * 10^(-5)) i + (3.9 * 10^(-5)) j

We have to first find the magnitude of the Magnetic field, |B|:

|B| = √{[3.0 * 10^(-5)]^2 + [3.9 * 10^(-5)^2]}

|B| = 4.92 * 10^(-5) T

The area of the floor is:

A = 25 * 15 = 375 m²

Therefore:

|Φ| = 4.92 * 10^(-5) * 375

|Φ| = 0.0185 Wb

The magnitude of the Magnetic Flux is 0.0185 Wb.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

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