In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separation between adjacent bright fringes on a screen 5 m from the slits is:a. 0.10 cm b. 0.25 cm c. 0.50 cm d. 1.0 cm e. none of the above

b. 0.25cm

Explanation:

You can solve this question by using the formula for the position of the fringes:

m: order of the fringes

lambda: wavelength 500nm

D: distance to the screen 5 m

d: separation of the slits 1mm=1*10^{-3}m

With the formula you can calculate the separation of two adjacent slits:

hence, the aswer is 0.25cm

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