An object is thrown upwards with a velocity of 3 meters per second, such that the only force acting on it is gravity (acceleration is -9.8). What will the object's velocity be after 2 seconds?

A.) -16.6 meters per second (down)
B.) 16.6 meters per second (up)
C.) -22.6 meters per second (down)
D.) 22.6 meters per second (up)
E.) 3 meters per second (up)

Correct  A.)  V = - 16.6 m/s down

Explanation:

Given:

V₀ = 3 m/s  initial velocity

t = 2 seconds

g = 9.8 m/s²

V(t) = V(2) = ?

The movement described is a vertical upward shot

For velocity at any time is valid the next formula

V = V₀ - g · t

V = 3 - (9.8 · 2) = 3 - 19.6 = - 16.6 m/s down

Under condition that it has a enough drop height with respect to the ejection point.

God is with you!!!