The portion of string between the bridge and upper end of the fingerboard (the part of the string that is free to vibrate) of a certain musical instrument is 60.0 cm long and has a mass of 2.85 g . The string sounds an A4 note (440 Hz ) when played.

Where must the player put a finger (at what distance x from the bridge) to play a D5 note (587 Hz )? (See the figure (Figure 1) ) For both notes, the string vibrates in its fundamental mode.

Without retuning, is it possible to play a G4 note (392 Hz ) on this string?

Explain your answer in part B: why or why not?

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft