Click on the boxes below to indicate the number of electrons or protons in each labeled position for a zinc atom (z=30, a=65). Please carefully note the specific information requested for the nucleus by the letter designation. A: 65, 35, or 30
B:0,2,4,6,3,5,1,8, or 7
C: 2,0,6,7,5,4,8,3, or 1
D: 18,16,0,10,8,2,20,6, or 4
E: 2,8,0,6,16,10,18,4, or 20

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we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer