Two plates with area 7.00×10−3 m27.00×10−3 m2 are separated by a distance of 4.80×10−4 m4.80×10−4 m . If a charge of 5.40×10−8 C5.40×10−8 C is moved from one plate to the other, calculate the potential difference (voltage) between the two plates. Assume that the separation distance is small in comparison to the diameter of the plates.

The voltage is    

Explanation:

From the question we are told that

    The area of the both plate is  

    The distance between the plate is

     The magnitude of the charge is  

The capacitance of the capacitor that consist of the two plates is mathematically represented as

Where is the permitivity of free space with a value  

So

The potential difference between the plate is mathematically represented as

answer: electrons