The position of an object moving along the x axis is given by x(t) = 2t^2+t^3 +1, where x is
in meters and t in seconds. The acceleration of
the object at t = 2 seconds is:

4m/s?

 16 meters per second

Explanation:

 The derivative of the position is the velocity.

 The derivative of the velocity is the acceleration.

                  x(t) = 2t² + t³ + 1

         x'(t) = v(t) = 4t + 3t²

x''(t) = v'(t) = a(t) = 4 + 6t

                  a(2) = 4 + 6(2)

                         = 4 + 12

                         = 16

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i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

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