A car and a truck, starting from rest, have the same acceleration, but the truck accelerates for twice the length of time. Compared with the car, the truck will travel:. a. twice as far.
b. one-half as far.
c. three times as far.
d. four times as far.
e. 1.4 times as far.

d. four times as far

Explanation:

Initial velocity of car and truck, u = 0

let acceleration of both the truck and car = a

let the length of time for the acceleration = t

Let the time the truck accelerated = 2t

The distance traveled by the car is calculated as;

s = ut + ¹/₂at²

s₁ = 0(t) + ¹/₂at²

s₁ = ¹/₂at²

The distance traveled by the truck is calculated as;

s = ut + ¹/₂at²

s₂ = 0(2t) + ¹/₂a (2t)²

s₂ =  ¹/₂a x 4t²

s₂ = 4 (¹/₂at²)

s₂ = 4(s₁)

Truck distance = four times car distance

Therefore, Compared with the car, the truck will travel four times as far

d. four times as far

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.