Anwer this quickly. Find the equivalent capacitance of the following combination.

When we have capacitors in series, with capacitances c1, c2, , cn, the total capacitance can be obtained from the equation:

1/ct  = 1/c1 + 1/c2 +

When we have capacitors in parallel, with capacitances c1, c2, ..., cn, the total capacitance can be obtained from the equation:

ct = c1 + c2 +

Ok, in this case we have two branches, and in each branch we have two capacitors in series.

So the capacitance of each branch will be:

1/ct = 1/c + 1/c = 2/c

ct = c/2.

Now we can think that we have two capacitors in parallel, each one with capacitance c/2.

So the total capacitance is:

ct = c/2 + c/2 = c.

(75°f − 32) × 5/9 = 23.889°c

temp rises, and expansion