A light plane must reach a speed of 33 m/s for takeoff. How long a runway is needed if the constant acceleration is 3.0 m/s2

181.5 m

Explanation:

From the question,

Applying the equation of motion,

v² = u²+2as Equation 1

Where a = acceleration of the light plane, v = final velocity of the light plane, u = initial velocity of the light plane, s = length of the runway.

make s the subject of formula in equation 1

s = (v²-u²)/2a Equation 2

Given: v = 33 m/s, u = 0 m/s(from rest), a = 3.0 m/s²

Substitute these values into equation 2

s = (33²-0²)/(2×3)

s = 1089/6

s = 181.5 m

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.