Physics, 03.09.2020 05:01 que40

Three. Grams of the same substance in different phases are stored in three different containers. Each container is barely large enough to hold the substance

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Answer from: nayelimoormann

Complete question is;

Three grams of the same substance in different phases are stored in three different containers. Each container is barely large enough to hold the substance. Which statement can be known about the behavior of the atoms in each container?

A) The atoms in the solid would be moving vigorously around the container.

B) The atoms in the liquid would be vibrating in position.

C) The atoms in the solid would be vibrating in position.

D) The atoms in the gas would be moving slowly around the container.

Option C - The atoms in the solid would be vibrating in position

Explanation:

Option A is wrong because the molecules in solids are held together by strong inter molecular forces and therefore can't move about freely but instead will vibrate in their position.

Option B is wrong because the atoms in liquid are more free than those in solids. Thus they will not have room to vibrate.

Option C is correct from the explanation from option A.

Option D is wrong because the atom of the gas would be very loose and free and would therefore be moving very fast around the container

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

Answer from: Quest

What the heck r u talkin bout? ?

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