You take a couple of capacitors and connect them in series, to which you observe a total capacitance of 4.8microfarads. However, when you connect them in parallel their combined capacitance is 35microfarads. Determine the value of each capacitor.

C₁ = 34.8 μF

C₂ = 0.2 μF

Explanation:

When the capacitors are connected in series their resultant capacitance is given by the formula:

Cs = 1/C₁ + 1/C₂

where,

Cs = Series equivalent capacitance = 4.8 μF

C₁ = Capacitance of 1st Capacitor

C₂ = Capacitance of 2nd Capacitor

Therefore,

4.8 μF = 1/C₁ + 1/C₂

(4.8 μF)(C₁ C₂) = C₁ + C₂   equation 1

When the capacitors are connected in parallel their resultant capacitance is given by the formula:

Cp = C₁ + C₂

where,

Cp = Parallel equivalent capacitance = 35 μF

Therefore,

35 μF = C₁ + C₂   equation 2

solving equation 1 and equation 2 simultaneously, we get:

C₁ = 34.8 μF

C₂ = 0.2 μF

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

e/c, where e is its total energy