Physics, 12.10.2020 01:01 violet9139

This is a big project that's due in like 30 minutes Explain how force (F=ma), momentum (p=mv), energy, and gravity play a part in your launching sequence. And a Drawing of your rocket (include vectors(remember arrows show direction and magnitude). Please draw this on paper

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turns on the engines that transforms the chemical energy of its components into mechanical energy that they supply to the rocket, so that the amount of chemical energy of the fuel decreases and increases the potential energy (height) and the kinetic energy (speed).

Explanation:

In this exercise we must describe what happens when a rocket is launched.

At the beginning, the whole system is at rest, the force is the weight and the normal.

At this time, it turns on the engines that transforms the chemical energy of its components into mechanical energy that they supply to the rocket, so that the amount of chemical energy of the fuel decreases and increases the potential energy (height) and the kinetic energy (speed). At this point, the system can also be analyzed by an increase in its momentum due to the impulse given by the engines, the two forms of analysis are correct and allow to find different magnitudes of the system, we must emphasize that the mass of the rocket decreases, but the rocket mass plus exhaust gases remains constant.

At that point when the rocket begins to climb, the support on the Earth decreases to zero and the Normal Force is zero.

When all the chemical energy of the engines is finished, they are released and other engines are turned on that, as the weight has decreased, can continue to give energy to the rocket to continue its increase in scientific and potential energy. In this second case, the impulse is different since other fuels are used, it is appropriate to clarify that the weight of the rocket decreases due to the loss of mass of the engines that were released and also due to the decrease in the force of gravity of the planet with height

In the attachment we can see a diagram of the moment of clearance, just after the normal force becomes zero

This is a big project that's due in like 30 minutes Explain how force (F=ma), momentum (p=mv), energ

Answer from: Quest

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

Answer from: Quest

here we know that ball will drop down by total distance 3.2 m

so here we know that

$v_{yi} = 0$

$\delta y = - 3.2 m$

now using kinematics

$\delta y = v_{yi} t + \frac{1}{2}at^2$

$-3.2 = 0 -\frac{1}{2}(9.8) t^2$

$t = 0.81 s$

now in the same time it will cover horizontal distance of 0.75 m

$\delta x = 0.75m$

so speed of the ball will be

$v = \frac{delta x }{\delta t}$

$v = \frac{0.75}{0.81} = 0.93 m/s$

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