pls help asap pls explain. Just before opening her parachute a skydiver having a mass of 50 kg reaches terminal velocity. Calculate the force of air resistance if the buoyant force is 20 N. Be careful! Use the skydiver’s mass to calculate his/her Fg (force of gravity).

490N

Explanation:

Given that,

Mass of a skydiver, m = 50 kg

Buoyant force = 20 N

When the skydiver reaches the terminal velocity, net force on her is equal to 0. So, air drag is equal to the weight of the skydiver.

D = mg

Putting all the values,

D = 50 × 9.8

D = 490 N

So, the force of air resistance is 490 N.

answer; how far out of place which the object finished relative to the starting location;

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y