At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 810 m/s2 and the vertical or y component of its acceleration is 910 m/s2. The ball's mass is 0.40 kg. What is the magnitude of the net force acting on the soccer ball at this instant?

487.13N

Explanation:

According to Newton's second law;

F = ma

F is the net force

m is the mass of the object

a is the acceleration

First we need to find the resultant of the acceleration

a =√810²+910²

a = √656,100+828,100

a =√1,484,200

a = 1218.28m/s²

Ball mass = 0.40kg

Next is to get the magnitude of the net force

F = 0.4 × 1218.28

F = 487.31N

Hence the magnitude of the net force acting on the soccer ball at this instant is 487.13N

it is b

explanation: