How much heat is released when 30 g of water at 96 °C cools to 16 °C ? The specific heat of water is 4184 J/kg°C

10 041.6 J

Explanation:

The equation for heat (energy) lost or gained by a system is

Q=mcΔT

Where Q is heat

m is the mass in kilograms

c is the specific heat of a substance

and T is the change in temperature

To start we convert 30g to kg by dividing by 1000

30/1000=0.03kg

We can now plug in all our values

Q= 0.03×4184×(96-16)= 10 041.6J

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