20 points - Brainliest A rock is thrown horizontally from a cliff at 40 m/s. If the rock lands 155 meters from the base of the cliff. How long was the rock in the air?

The known values are: \text{t}=2.35\:\text{s};\:\text{y}=0\:\text{m};\:\text{v}_0=+8.00\:\text{m/s};\:\text{a}=-9.8\:\text{m/s}^2

Based from the given values, we can use the equation y=y_0+v_0t+\frac{1}{2}at^2. Substituting the values, we have

0\:=\text{y}_0+\left(8.00\:\text{m/s}\right)\left(2.35\:\text{s}\right)+\frac{1}{2}\left(-9.80\:\text{m/s}^2\right)\left(2.35\:\text{s}\right)^2

y=8.26\:m

Therefore, the cliff is 8.26 meters high.

Explanation:

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop