Robin throws a penny up in the air. If the penny's initial velocity is 1.0m/s[up] and it is launched from a height of 1.5 m, what is the maximum height of the penny above the ground?

1.55m

Explanation:

The formula for calculating the maximum height is expressed as;

H = u²/2g

u is the initial velocity

g is the acceleration due to gravity

Substitute

H = 1²/2(9.8)

H = 1/19.6

H = 0.051m

Since it is launched form a height of 1.5m, the height above the ground will be 1.5+0.051 = 1.55m

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