You push a manual lawn mower across the lawn at constant speed. What is the value of the coefficient of friction between the mower and the grass

Explanation:

The question is incomplete. Here is the complete question:

You are pushing a 13.3 kg lawn mower across the lawn with a force of 200 N. What is the value of the coefficient of friction between the mower and the grass if the mower moves with a constant velocity? The force is applied downward at an angle of 65° with the horizontal.

According to Newton's second law of motion:

Fapp is the applied force = 200N

Ff is the frictional force

is the coefficient of friction between the mower and the grass

R is the reaction

m is the mass of the object

ax is the acceleration

Given

R = mg = 13.3*9.8

R = 130.34N

m = 13.3kg

ax  = 0m/s² (constant velocity)

Fapp = 200N

Substitute the given parameters into the formula and get the coefficient of friction as shown;

Recall that:

Hence the coefficient of friction between the mower and the grass is 0.27

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the answer is a. at the equator